India lost both their openers early as they reached 55 for two in nine overs against Australia in the third One-Day International (ODI) at the Punjab Cricket Association (PCA) Stadium in Mohali on Saturday.
Australia brought in Shane Watson in the seventh over of the match as the first change bowler and the move worked immediately as he dismissed Rohit Sharma who tried to pull but edged it and Aaron Finch ran back from slips to take an easy catch.
The even green cover on the pitch made it evident that it won’t be as easy for the batsmen in Mohali as it was in Jaipur in the previous encounter. However, Kohli was in complete control as he hit some crisp boundaries.
Earlier, Australia skipper George Bailey won the toss and elected to field first. It was only the second time in 28 games in the country that Australia won the toss and put Indian in to bat first. However, with dew expected to play an important role later in the day and the brutal assault by the Indian batsmen, it was an expected decision.
The Indian innings got off to a quiet start, with the two runs coming off wide deliveries. The first run off the bat came off the eighth delivery as Dhawan played an exquisite cover drive for a boundary. However, Clint McKay returned to beat Dhawan’s bat with an away-going delivery outside off. Dhawan came back to flick a delivery off his legs for another boundary. Nonethless, McKay eventually won the battle as he squared Dhawan with an off-cutter t find an edge which is bsafely pouched by the wicketkeeper.
Rohit Sharma was lucky as an inside edge missed the stumps and the keeper to race away to a boundary in the fourth over.