Manoj Tiwary, Ambati Rayudu star in India A’s 5-wicket win over Australia A
Rayudu scored 77 not out and Tiwary had taken five wickets.
Ambati Rayudu scored 77 not out in India A’s run-chase © AFP
Jul 31, 2014
India A have beaten Australia A by five wickets in the Quadrangular Series Down Under. It was a game where Manoj Tiwary starred with the ball as his figures of five for 34 stunned the hosts and bowled them out for 228. In reply, India A were led by Ambati Rayudu, Kedar Jadhav and Sanju Samson as they won the game with 13 balls to spare.
Chasing 228, India A lost early wickets and had stumbled to three for 38. But, Rayudu constructed a good stand of 101 with Jadhav. The Maharashtra batsman, Jadhav, scored 52 off 50 balls before he was dismissed by Cameron White. That did not deter India as Samson joined in and scored 49 not out. Rayudu remained unbeaten on 77. With this win, India remain on the top of the table in this quadrangular series.
Earlier, Marcus Stoinis and Phil Hughes started off well with the former smashing 58 before being dismissed. Hughes continued and got 58 as well. At one stage, they were 126 for one, when Tiwary removed Peter Nevill. He then removed Cameron White for seven and then had the important wicket of Hughes reducing Australia A to 157 for four. Two off those wickets were stumped and one was caught.
It did not stop there as he then had Tom Cooper and Alex Doolan out to get his five-for. From 180 for six, Australia A somehow managed to get across to 228 and were bowled out with two balls to spare. Akshar Patel played a big role as he and Ambati Rayudu cleaned up the tail.
Australia A 228 in 49.4 overs (Marcus Stoinis 58, Phil Hughes 58; Manoj Tiwary 5 for 34, Akshar Patel 3 for 30) lost to India A 231 for 5 in 47.5 overs (Ambati Rayudu 77*, Kedar Jadhav 52, Sanju Samson 49; Clint McKay 1 for 19) by 5 wickets.