All matches up to the finals will be held in the best of 7 format, while the finals would be best of 9 © Getty Images (Representational Image)
All matches up to the finals will be held in the best of 7 format, while the finals would be best of 9 © Getty Images (Representational Image)

Hyderabad: The third edition of the World Ranking Snooker Championship Indian Open would be held from July 5 to 9. The tournament will start with the six Indian wild cards playing the qualifying matches. Defending champion Michael White would be seen playing the qualifiers along with Anthony Hamilton. Aditya Mehta would be playing Jimmy Robertson, a release from the Billiards and Snooker Federation of India (BFSI) said. All matches up to the finals will be held in the best of 7 format, while the finals would be best of 9. The entire event will be played on four match tables, it said.

Promising an exciting championship, it said every session will be kicked off by a celebrity on all the days of the event. The inaugural function will be held on July 4 at 7pm onwards at the venue, the Hyderabad International Convention Centre (HICC).