Published: Oct 17, 2013, 04:37 PM (IST)
Edited: Oct 17, 2013, 04:37 PM (IST)
Saeed Ajmal took four wickets in South Africa’s second innings © AFP
Oct 17, 2013
Pakistan need 40 runs to win the first Test against South Africa and take a 1-0 lead in the two-match series. South Africa were bowled out for 232 in their second innings as tea was taken on Day Four at the Sheikh Zayed Stadium in Abu Dhabi on Thursday.
South Africa were at a precarious 130 for six at lunch as Pakistan looked set for an innings victory. They trailed Pakistan by 63 runs. But AB de Villiers scored a gritty 90 off 157 balls to ensure Pakistan had to bat again. When the afternoon session began, De Villiers was accompanied by Faf du Plesis.
But soon after lunch, Du Plesis was dismissed by Saeed Ajmal caught and bowled. Then came a 57-run partnership between De Villiers and Robin Peterson for the eighth-wicket. De Villiers struck seven fours and one six in his innings.
Junaid Khan then got the prized wicket of De Villiers. A length delivery was hit on the up and caught by Shan Masood at covers. South Africa were still three runs behind Pakistan’s 442 in the first innings. But Peterson and Vernon Philander added a crucial 42 for the ninth-wicket.
But the resistance could not last long as off-spinner Ajmal struck and dismissed Philander for 10. The batsman edged the delivery and wicketkeeper Adnan Akmal juggled at the attempt, but held on. Two balls later, Morne Morkel was also caught and bowled by Ajmal as South Africa were bowled out for 232. Tea was taken immediately.
Brief scores:
South Africa 249 (Hashim Amla 118, JP Duminy 57; Mohammad Irfan 3 for 44) and 232 (AB de Villiers 90, Robin Peterson 47*; Saeed Ajmal 4 for 74, Junaid Khan 3 for 57) lead Pakistan 442 (Khurram Manzoor 146, Shan Masood 75, Misbah-ul-Haq 100, Asad Shafiq 54; Vernon Philander 3 for 84, Dale Steyn 3 for 88) by 39 runs.
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